PSLEIn the figure, GHJK is a straight line, HKLM is a parallelogram and LJ = LM. ∠MGH is a right angle, ∠GMH = 36° and ∠KLJ = 22°.
- Find ∠n.
- Find ∠p.
(a)
∠MGH = 90° (Right angle)
∠n
= 90° + 36°
= 126° (Exterior angle of a triangle)
(b)
∠KLM = ∠KHM = 126° (Parallelogram)
∠JLM
= 126° - 22°
= 104°
∠p
= (180° - 104°) ÷ 2
= 38° (Isosceles triangle)
Answer(s): (a) 126°; (b) 38°