PSLE In the figure, FGLM is a parallelogram and HJKL is a rhombus. MLK is a straight line. ∠GFM = 56°, ∠LGH = 29° and ∠JHK = 33°.
- Find ∠GLH.
- Find ∠GHJ.
(a)
∠GLM
= ∠GFM
= 56° (Parallelogram)
∠JKH
= ∠JHK
= 33° (Isosceles triangle)
∠HJK
= 180° - 33° - 33°
= 108° (Angles sum of triangle)
∠HLK
= ∠HJK
= 108° (Rhombus)
∠GLH
= 180° - 56° - 108°
= 16° (Angles on a straight line)
(b)
∠GHL
= 180° - 29° - 16°
= 135° (Angles sum of triangle)
∠KHL
= ∠JHK
= 33° (Rhombus)
∠GHJ
= 360° - 135° - 33° - 33°
= 159° (Angles at a point)
Answer(s): (a) 16°; (b) 159°