PSLE In the figure, FGLM is a parallelogram and HJKL is a rhombus. MLK is a straight line. ∠GFM = 56°, ∠LGH = 28° and ∠JHK = 32°.
- Find ∠GLH.
- Find ∠GHJ.
(a)
∠GLM
= ∠GFM
= 56° (Parallelogram)
∠JKH
= ∠JHK
= 32° (Isosceles triangle)
∠HJK
= 180° - 32° - 32°
= 109° (Angles sum of triangle)
∠HLK
= ∠HJK
= 109° (Rhombus)
∠GLH
= 180° - 56° - 109°
= 15° (Angles on a straight line)
(b)
∠GHL
= 180° - 28° - 15°
= 137° (Angles sum of triangle)
∠KHL
= ∠JHK
= 32° (Rhombus)
∠GHJ
= 360° - 137° - 32° - 32°
= 159° (Angles at a point)
Answer(s): (a) 15°; (b) 159°