PSLE In the figure, HJNP is a parallelogram and KLMN is a rhombus. PNM is a straight line. ∠JHP = 56°, ∠NJK = 29° and ∠LKM = 34°.
- Find ∠JNK.
- Find ∠JKL.
(a)
∠JNP
= ∠JHP
= 56° (Parallelogram)
∠LMK
= ∠LKM
= 34° (Isosceles triangle)
∠KLM
= 180° - 34° - 34°
= 103° (Angles sum of triangle)
∠KNM
= ∠KLM
= 103° (Rhombus)
∠JNK
= 180° - 56° - 103°
= 21° (Angles on a straight line)
(b)
∠JKN
= 180° - 29° - 21°
= 130° (Angles sum of triangle)
∠MKN
= ∠LKM
= 34° (Rhombus)
∠JKL
= 360° - 130° - 34° - 34°
= 162° (Angles at a point)
Answer(s): (a) 21°; (b) 162°