PSLE In the figure, EFKL is a parallelogram and GHJK is a rhombus. LKJ is a straight line. ∠FEL = 61°, ∠KFG = 27° and ∠HGJ = 32°.
- Find ∠FKG.
- Find ∠FGH.
(a)
∠FKL
= ∠FEL
= 61° (Parallelogram)
∠HJG
= ∠HGJ
= 32° (Isosceles triangle)
∠GHJ
= 180° - 32° - 32°
= 103° (Angles sum of triangle)
∠GKJ
= ∠GHJ
= 103° (Rhombus)
∠FKG
= 180° - 61° - 103°
= 16° (Angles on a straight line)
(b)
∠FGK
= 180° - 27° - 16°
= 137° (Angles sum of triangle)
∠JGK
= ∠HGJ
= 32° (Rhombus)
∠FGH
= 360° - 137° - 32° - 32°
= 159° (Angles at a point)
Answer(s): (a) 16°; (b) 159°