PSLE In the figure, FGLM is a parallelogram and HJKL is a rhombus. MLK is a straight line. ∠GFM = 59°, ∠LGH = 29° and ∠JHK = 32°.
- Find ∠GLH.
- Find ∠GHJ.
(a)
∠GLM
= ∠GFM
= 59° (Parallelogram)
∠JKH
= ∠JHK
= 32° (Isosceles triangle)
∠HJK
= 180° - 32° - 32°
= 107° (Angles sum of triangle)
∠HLK
= ∠HJK
= 107° (Rhombus)
∠GLH
= 180° - 59° - 107°
= 14° (Angles on a straight line)
(b)
∠GHL
= 180° - 29° - 14°
= 137° (Angles sum of triangle)
∠KHL
= ∠JHK
= 32° (Rhombus)
∠GHJ
= 360° - 137° - 32° - 32°
= 159° (Angles at a point)
Answer(s): (a) 14°; (b) 159°