PSLE In the figure, EFKL is a parallelogram and GHJK is a rhombus. LKJ is a straight line. ∠FEL = 57°, ∠KFG = 29° and ∠HGJ = 33°.
- Find ∠FKG.
- Find ∠FGH.
(a)
∠FKL
= ∠FEL
= 57° (Parallelogram)
∠HJG
= ∠HGJ
= 33° (Isosceles triangle)
∠GHJ
= 180° - 33° - 33°
= 104° (Angles sum of triangle)
∠GKJ
= ∠GHJ
= 104° (Rhombus)
∠FKG
= 180° - 57° - 104°
= 19° (Angles on a straight line)
(b)
∠FGK
= 180° - 29° - 19°
= 132° (Angles sum of triangle)
∠JGK
= ∠HGJ
= 33° (Rhombus)
∠FGH
= 360° - 132° - 33° - 33°
= 162° (Angles at a point)
Answer(s): (a) 19°; (b) 162°