PSLE In the figure, ABFG is a parallelogram and CDEF is a rhombus. GFE is a straight line. ∠BAG = 61°, ∠FBC = 29° and ∠DCE = 32°.
- Find ∠BFC.
- Find ∠BCD.
(a)
∠BFG
= ∠BAG
= 61° (Parallelogram)
∠DEC
= ∠DCE
= 32° (Isosceles triangle)
∠CDE
= 180° - 32° - 32°
= 102° (Angles sum of triangle)
∠CFE
= ∠CDE
= 102° (Rhombus)
∠BFC
= 180° - 61° - 102°
= 17° (Angles on a straight line)
(b)
∠BCF
= 180° - 29° - 17°
= 134° (Angles sum of triangle)
∠ECF
= ∠DCE
= 32° (Rhombus)
∠BCD
= 360° - 134° - 32° - 32°
= 162° (Angles at a point)
Answer(s): (a) 17°; (b) 162°