PSLE In the figure, TUYZ is a parallelogram and VWXY is a rhombus. ZYX is a straight line. ∠UTZ = 56°, ∠YUV = 29° and ∠WVX = 36°.
- Find ∠UYV.
- Find ∠UVW.
(a)
∠UYZ
= ∠UTZ
= 56° (Parallelogram)
∠WXV
= ∠WVX
= 36° (Isosceles triangle)
∠VWX
= 180° - 36° - 36°
= 102° (Angles sum of triangle)
∠VYX
= ∠VWX
= 102° (Rhombus)
∠UYV
= 180° - 56° - 102°
= 22° (Angles on a straight line)
(b)
∠UVY
= 180° - 29° - 22°
= 129° (Angles sum of triangle)
∠XVY
= ∠WVX
= 36° (Rhombus)
∠UVW
= 360° - 129° - 36° - 36°
= 159° (Angles at a point)
Answer(s): (a) 22°; (b) 159°