PSLE In the figure, FGLM is a parallelogram and HJKL is a rhombus. MLK is a straight line. ∠GFM = 56°, ∠LGH = 28° and ∠JHK = 33°.
- Find ∠GLH.
- Find ∠GHJ.
(a)
∠GLM
= ∠GFM
= 56° (Parallelogram)
∠JKH
= ∠JHK
= 33° (Isosceles triangle)
∠HJK
= 180° - 33° - 33°
= 106° (Angles sum of triangle)
∠HLK
= ∠HJK
= 106° (Rhombus)
∠GLH
= 180° - 56° - 106°
= 18° (Angles on a straight line)
(b)
∠GHL
= 180° - 28° - 18°
= 134° (Angles sum of triangle)
∠KHL
= ∠JHK
= 33° (Rhombus)
∠GHJ
= 360° - 134° - 33° - 33°
= 160° (Angles at a point)
Answer(s): (a) 18°; (b) 160°