PSLE In the figure, GHMN is a parallelogram and JKLM is a rhombus. NML is a straight line. ∠HGN = 58°, ∠MHJ = 29° and ∠KJL = 32°.
- Find ∠HMJ.
- Find ∠HJK.
(a)
∠HMN
= ∠HGN
= 58° (Parallelogram)
∠KLJ
= ∠KJL
= 32° (Isosceles triangle)
∠JKL
= 180° - 32° - 32°
= 103° (Angles sum of triangle)
∠JML
= ∠JKL
= 103° (Rhombus)
∠HMJ
= 180° - 58° - 103°
= 19° (Angles on a straight line)
(b)
∠HJM
= 180° - 29° - 19°
= 132° (Angles sum of triangle)
∠LJM
= ∠KJL
= 32° (Rhombus)
∠HJK
= 360° - 132° - 32° - 32°
= 164° (Angles at a point)
Answer(s): (a) 19°; (b) 164°