PSLE In the figure, HJNP is a parallelogram and KLMN is a rhombus. PNM is a straight line. ∠JHP = 56°, ∠NJK = 29° and ∠LKM = 33°.
- Find ∠JNK.
- Find ∠JKL.
(a)
∠JNP
= ∠JHP
= 56° (Parallelogram)
∠LMK
= ∠LKM
= 33° (Isosceles triangle)
∠KLM
= 180° - 33° - 33°
= 106° (Angles sum of triangle)
∠KNM
= ∠KLM
= 106° (Rhombus)
∠JNK
= 180° - 56° - 106°
= 18° (Angles on a straight line)
(b)
∠JKN
= 180° - 29° - 18°
= 133° (Angles sum of triangle)
∠MKN
= ∠LKM
= 33° (Rhombus)
∠JKL
= 360° - 133° - 33° - 33°
= 161° (Angles at a point)
Answer(s): (a) 18°; (b) 161°