PSLE In the figure, DEJK is a parallelogram and FGHJ is a rhombus. KJH is a straight line. ∠EDK = 58°, ∠JEF = 29° and ∠GFH = 34°.
- Find ∠EJF.
- Find ∠EFG.
(a)
∠EJK
= ∠EDK
= 58° (Parallelogram)
∠GHF
= ∠GFH
= 34° (Isosceles triangle)
∠FGH
= 180° - 34° - 34°
= 104° (Angles sum of triangle)
∠FJH
= ∠FGH
= 104° (Rhombus)
∠EJF
= 180° - 58° - 104°
= 18° (Angles on a straight line)
(b)
∠EFJ
= 180° - 29° - 18°
= 133° (Angles sum of triangle)
∠HFJ
= ∠GFH
= 34° (Rhombus)
∠EFG
= 360° - 133° - 34° - 34°
= 159° (Angles at a point)
Answer(s): (a) 18°; (b) 159°