PSLE In the figure, GHMN is a parallelogram and JKLM is a rhombus. NML is a straight line. ∠HGN = 62°, ∠MHJ = 28° and ∠KJL = 32°.
- Find ∠HMJ.
- Find ∠HJK.
(a)
∠HMN
= ∠HGN
= 62° (Parallelogram)
∠KLJ
= ∠KJL
= 32° (Isosceles triangle)
∠JKL
= 180° - 32° - 32°
= 102° (Angles sum of triangle)
∠JML
= ∠JKL
= 102° (Rhombus)
∠HMJ
= 180° - 62° - 102°
= 16° (Angles on a straight line)
(b)
∠HJM
= 180° - 28° - 16°
= 136° (Angles sum of triangle)
∠LJM
= ∠KJL
= 32° (Rhombus)
∠HJK
= 360° - 136° - 32° - 32°
= 160° (Angles at a point)
Answer(s): (a) 16°; (b) 160°