PSLE In the figure, HJNP is a parallelogram and KLMN is a rhombus. PNM is a straight line. ∠JHP = 58°, ∠NJK = 27° and ∠LKM = 32°.
- Find ∠JNK.
- Find ∠JKL.
(a)
∠JNP
= ∠JHP
= 58° (Parallelogram)
∠LMK
= ∠LKM
= 32° (Isosceles triangle)
∠KLM
= 180° - 32° - 32°
= 102° (Angles sum of triangle)
∠KNM
= ∠KLM
= 102° (Rhombus)
∠JNK
= 180° - 58° - 102°
= 20° (Angles on a straight line)
(b)
∠JKN
= 180° - 27° - 20°
= 133° (Angles sum of triangle)
∠MKN
= ∠LKM
= 32° (Rhombus)
∠JKL
= 360° - 133° - 32° - 32°
= 163° (Angles at a point)
Answer(s): (a) 20°; (b) 163°