PSLE In the figure, LMNP is a parallelogram. JPL and KPN are straight lines and JK = KL. ∠JKP = 27° and ∠MNP = 56°.
- Find ∠NPL.
- Find ∠PKL.
(a)
∠NPL
= 180° - 56°
= 124° (Interior angles)
(b)
∠JPK
= ∠NPL
= 124° (Vertically opposite angles)
∠KJP
= 180° - 124° - 27°
= 29° (Angles sum of triangle)
∠KLP = ∠KJP (Isosceles triangle)
∠JKL
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠PKL
= 122° - 27°
= 95°
Answer(s): (a) 124°; (b) 95°