PSLE In the figure, JKLM is a parallelogram. GMJ and HML are straight lines and GH = HJ. ∠GHM = 31° and ∠KLM = 58°.
- Find ∠LMJ.
- Find ∠MHJ.
(a)
∠LMJ
= 180° - 58°
= 122° (Interior angles)
(b)
∠GMH
= ∠LMJ
= 122° (Vertically opposite angles)
∠HGM
= 180° - 122° - 31°
= 27° (Angles sum of triangle)
∠HJM = ∠HGM (Isosceles triangle)
∠GHJ
= 180° - 27° - 27°
= 126° (Angles sum of triangle)
∠MHJ
= 126° - 31°
= 95°
Answer(s): (a) 122°; (b) 95°