PSLE In the figure, HJKL is a parallelogram. FLH and GLK are straight lines and FG = GH. ∠FGL = 31° and ∠JKL = 59°.
- Find ∠KLH.
- Find ∠LGH.
(a)
∠KLH
= 180° - 59°
= 121° (Interior angles)
(b)
∠FLG
= ∠KLH
= 121° (Vertically opposite angles)
∠GFL
= 180° - 121° - 31°
= 28° (Angles sum of triangle)
∠GHL = ∠GFL (Isosceles triangle)
∠FGH
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠LGH
= 124° - 31°
= 93°
Answer(s): (a) 121°; (b) 93°