PSLE In the figure, QRST is a parallelogram. NTQ and PTS are straight lines and NP = PQ. ∠NPT = 32° and ∠RST = 56°.
- Find ∠STQ.
- Find ∠TPQ.
(a)
∠STQ
= 180° - 56°
= 124° (Interior angles)
(b)
∠NTP
= ∠STQ
= 124° (Vertically opposite angles)
∠PNT
= 180° - 124° - 32°
= 24° (Angles sum of triangle)
∠PQT = ∠PNT (Isosceles triangle)
∠NPQ
= 180° - 24° - 24°
= 132° (Angles sum of triangle)
∠TPQ
= 132° - 32°
= 100°
Answer(s): (a) 124°; (b) 100°