PSLE In the figure, JKLM is a parallelogram. GMJ and HML are straight lines and GH = HJ. ∠GHM = 28° and ∠KLM = 56°.
- Find ∠LMJ.
- Find ∠MHJ.
(a)
∠LMJ
= 180° - 56°
= 124° (Interior angles)
(b)
∠GMH
= ∠LMJ
= 124° (Vertically opposite angles)
∠HGM
= 180° - 124° - 28°
= 28° (Angles sum of triangle)
∠HJM = ∠HGM (Isosceles triangle)
∠GHJ
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠MHJ
= 124° - 28°
= 96°
Answer(s): (a) 124°; (b) 96°