PSLE In the figure, HJKL is a parallelogram. FLH and GLK are straight lines and FG = GH. ∠FGL = 28° and ∠JKL = 55°.
- Find ∠KLH.
- Find ∠LGH.
(a)
∠KLH
= 180° - 55°
= 125° (Interior angles)
(b)
∠FLG
= ∠KLH
= 125° (Vertically opposite angles)
∠GFL
= 180° - 125° - 28°
= 27° (Angles sum of triangle)
∠GHL = ∠GFL (Isosceles triangle)
∠FGH
= 180° - 27° - 27°
= 126° (Angles sum of triangle)
∠LGH
= 126° - 28°
= 98°
Answer(s): (a) 125°; (b) 98°