PSLE In the figure, LMNP is a parallelogram. JPL and KPN are straight lines and JK = KL. ∠JKP = 32° and ∠MNP = 55°.
- Find ∠NPL.
- Find ∠PKL.
(a)
∠NPL
= 180° - 55°
= 125° (Interior angles)
(b)
∠JPK
= ∠NPL
= 125° (Vertically opposite angles)
∠KJP
= 180° - 125° - 32°
= 23° (Angles sum of triangle)
∠KLP = ∠KJP (Isosceles triangle)
∠JKL
= 180° - 23° - 23°
= 134° (Angles sum of triangle)
∠PKL
= 134° - 32°
= 102°
Answer(s): (a) 125°; (b) 102°