PSLE In the figure, UVWX is a parallelogram. SXU and TXW are straight lines and ST = TU. ∠STX = 28° and ∠VWX = 58°.
- Find ∠WXU.
- Find ∠XTU.
(a)
∠WXU
= 180° - 58°
= 122° (Interior angles)
(b)
∠SXT
= ∠WXU
= 122° (Vertically opposite angles)
∠TSX
= 180° - 122° - 28°
= 30° (Angles sum of triangle)
∠TUX = ∠TSX (Isosceles triangle)
∠STU
= 180° - 30° - 30°
= 120° (Angles sum of triangle)
∠XTU
= 120° - 28°
= 92°
Answer(s): (a) 122°; (b) 92°