PSLE In the figure, JKLM is a parallelogram. GMJ and HML are straight lines and GH = HJ. ∠GHM = 27° and ∠KLM = 57°.
- Find ∠LMJ.
- Find ∠MHJ.
(a)
∠LMJ
= 180° - 57°
= 123° (Interior angles)
(b)
∠GMH
= ∠LMJ
= 123° (Vertically opposite angles)
∠HGM
= 180° - 123° - 27°
= 30° (Angles sum of triangle)
∠HJM = ∠HGM (Isosceles triangle)
∠GHJ
= 180° - 30° - 30°
= 120° (Angles sum of triangle)
∠MHJ
= 120° - 27°
= 93°
Answer(s): (a) 123°; (b) 93°