PSLE In the figure, FGHJ is a parallelogram. DJF and EJH are straight lines and DE = EF. ∠DEJ = 22° and ∠GHJ = 55°.
- Find ∠HJF.
- Find ∠JEF.
(a)
∠HJF
= 180° - 55°
= 125° (Interior angles)
(b)
∠DJE
= ∠HJF
= 125° (Vertically opposite angles)
∠EDJ
= 180° - 125° - 22°
= 33° (Angles sum of triangle)
∠EFJ = ∠EDJ (Isosceles triangle)
∠DEF
= 180° - 33° - 33°
= 114° (Angles sum of triangle)
∠JEF
= 114° - 22°
= 92°
Answer(s): (a) 125°; (b) 92°