PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 49°, ∠KLM = 118° and ∠NPL = 70°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 49°
= 41° (Angles sum of triangle)
∠NLP
= 180° - 70° - 41°
= 69° (Angles sum of triangle)
∠KLP
= 180° - 69°
= 118° (Angles on a straight line)
(b)
∠NLM
= 360° - 118° - 69° - 118°
= 55° (Angles at a point)
∠LMN
= 180° - 55° - 55°
= 70°
Answer(s): (a) 118°; (b) 70°