PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 49°, ∠KLM = 115° and ∠NPL = 67°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 49°
= 41° (Angles sum of triangle)
∠NLP
= 180° - 67° - 41°
= 72° (Angles sum of triangle)
∠KLP
= 180° - 72°
= 115° (Angles on a straight line)
(b)
∠NLM
= 360° - 115° - 72° - 115°
= 58° (Angles at a point)
∠LMN
= 180° - 58° - 58°
= 64°
Answer(s): (a) 115°; (b) 64°