PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 54°, ∠EFG = 117° and ∠HJF = 66°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
∠HFJ
= 180° - 66° - 36°
= 78° (Angles sum of triangle)
∠EFJ
= 180° - 78°
= 117° (Angles on a straight line)
(b)
∠HFG
= 360° - 117° - 78° - 117°
= 48° (Angles at a point)
∠FGH
= 180° - 48° - 48°
= 84°
Answer(s): (a) 117°; (b) 84°