PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 48°, ∠EFG = 113° and ∠HJF = 70°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 48°
= 42° (Angles sum of triangle)
∠HFJ
= 180° - 70° - 42°
= 68° (Angles sum of triangle)
∠EFJ
= 180° - 68°
= 113° (Angles on a straight line)
(b)
∠HFG
= 360° - 113° - 68° - 113°
= 66° (Angles at a point)
∠FGH
= 180° - 66° - 66°
= 48°
Answer(s): (a) 113°; (b) 48°