PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 54°, ∠KLM = 123° and ∠NPL = 72°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
∠NLP
= 180° - 72° - 36°
= 72° (Angles sum of triangle)
∠KLP
= 180° - 72°
= 123° (Angles on a straight line)
(b)
∠NLM
= 360° - 123° - 72° - 123°
= 42° (Angles at a point)
∠LMN
= 180° - 42° - 42°
= 96°
Answer(s): (a) 123°; (b) 96°