PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 54°, ∠KLM = 124° and ∠NPL = 66°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
∠NLP
= 180° - 66° - 36°
= 78° (Angles sum of triangle)
∠KLP
= 180° - 78°
= 124° (Angles on a straight line)
(b)
∠NLM
= 360° - 124° - 78° - 124°
= 34° (Angles at a point)
∠LMN
= 180° - 34° - 34°
= 112°
Answer(s): (a) 124°; (b) 112°