PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 55°, ∠KLM = 114° and ∠NPL = 63°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 55°
= 35° (Angles sum of triangle)
∠NLP
= 180° - 63° - 35°
= 82° (Angles sum of triangle)
∠KLP
= 180° - 82°
= 114° (Angles on a straight line)
(b)
∠NLM
= 360° - 114° - 82° - 114°
= 50° (Angles at a point)
∠LMN
= 180° - 50° - 50°
= 80°
Answer(s): (a) 114°; (b) 80°