PSLE In the figure, DEG and JHG are straight lines and HE is parallel to GF. ∠HJD is a right angle, ∠JDE = 50°, ∠DEF = 110° and ∠GHE = 65°.
- Find ∠DEH.
- Find ∠EFG.
(a)
∠DGJ
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠GEH
= 180° - 65° - 40°
= 75° (Angles sum of triangle)
∠DEH
= 180° - 75°
= 110° (Angles on a straight line)
(b)
∠GEF
= 360° - 110° - 75° - 110°
= 65° (Angles at a point)
∠EFG
= 180° - 65° - 65°
= 50°
Answer(s): (a) 110°; (b) 50°