PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 53°, ∠EFG = 114° and ∠HJF = 72°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 53°
= 37° (Angles sum of triangle)
∠HFJ
= 180° - 72° - 37°
= 71° (Angles sum of triangle)
∠EFJ
= 180° - 71°
= 114° (Angles on a straight line)
(b)
∠HFG
= 360° - 114° - 71° - 114°
= 61° (Angles at a point)
∠FGH
= 180° - 61° - 61°
= 58°
Answer(s): (a) 114°; (b) 58°