PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 55°, ∠EFG = 112° and ∠HJF = 66°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 55°
= 35° (Angles sum of triangle)
∠HFJ
= 180° - 66° - 35°
= 79° (Angles sum of triangle)
∠EFJ
= 180° - 79°
= 112° (Angles on a straight line)
(b)
∠HFG
= 360° - 112° - 79° - 112°
= 57° (Angles at a point)
∠FGH
= 180° - 57° - 57°
= 66°
Answer(s): (a) 112°; (b) 66°