PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 53°, ∠KLM = 113° and ∠NPL = 69°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 53°
= 37° (Angles sum of triangle)
∠NLP
= 180° - 69° - 37°
= 74° (Angles sum of triangle)
∠KLP
= 180° - 74°
= 113° (Angles on a straight line)
(b)
∠NLM
= 360° - 113° - 74° - 113°
= 60° (Angles at a point)
∠LMN
= 180° - 60° - 60°
= 60°
Answer(s): (a) 113°; (b) 60°