PSLE In the figure, ABD and FED are straight lines and EB is parallel to DC. ∠EFA is a right angle, ∠FAB = 53°, ∠ABC = 113° and ∠DEB = 70°.
- Find ∠ABE.
- Find ∠BCD.
(a)
∠ADF
= 180° - 90° - 53°
= 37° (Angles sum of triangle)
∠DBE
= 180° - 70° - 37°
= 73° (Angles sum of triangle)
∠ABE
= 180° - 73°
= 113° (Angles on a straight line)
(b)
∠DBC
= 360° - 113° - 73° - 113°
= 61° (Angles at a point)
∠BCD
= 180° - 61° - 61°
= 58°
Answer(s): (a) 113°; (b) 58°