PSLE In the figure, ABD and FED are straight lines and EB is parallel to DC. ∠EFA is a right angle, ∠FAB = 55°, ∠ABC = 124° and ∠DEB = 71°.
- Find ∠ABE.
- Find ∠BCD.
(a)
∠ADF
= 180° - 90° - 55°
= 35° (Angles sum of triangle)
∠DBE
= 180° - 71° - 35°
= 74° (Angles sum of triangle)
∠ABE
= 180° - 74°
= 124° (Angles on a straight line)
(b)
∠DBC
= 360° - 124° - 74° - 124°
= 38° (Angles at a point)
∠BCD
= 180° - 38° - 38°
= 104°
Answer(s): (a) 124°; (b) 104°