PSLE In the figure, FGJ and LKJ are straight lines and KG is parallel to JH. ∠KLF is a right angle, ∠LFG = 50°, ∠FGH = 122° and ∠JKG = 72°.
- Find ∠FGK.
- Find ∠GHJ.
(a)
∠FJL
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠JGK
= 180° - 72° - 40°
= 68° (Angles sum of triangle)
∠FGK
= 180° - 68°
= 122° (Angles on a straight line)
(b)
∠JGH
= 360° - 122° - 68° - 122°
= 48° (Angles at a point)
∠GHJ
= 180° - 48° - 48°
= 84°
Answer(s): (a) 122°; (b) 84°