PSLE In the figure, DEG and JHG are straight lines and HE is parallel to GF. ∠HJD is a right angle, ∠JDE = 52°, ∠DEF = 121° and ∠GHE = 68°.
- Find ∠DEH.
- Find ∠EFG.
(a)
∠DGJ
= 180° - 90° - 52°
= 38° (Angles sum of triangle)
∠GEH
= 180° - 68° - 38°
= 74° (Angles sum of triangle)
∠DEH
= 180° - 74°
= 121° (Angles on a straight line)
(b)
∠GEF
= 360° - 121° - 74° - 121°
= 44° (Angles at a point)
∠EFG
= 180° - 44° - 44°
= 92°
Answer(s): (a) 121°; (b) 92°