PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 50°, ∠EFG = 115° and ∠HJF = 62°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠HFJ
= 180° - 62° - 40°
= 78° (Angles sum of triangle)
∠EFJ
= 180° - 78°
= 115° (Angles on a straight line)
(b)
∠HFG
= 360° - 115° - 78° - 115°
= 52° (Angles at a point)
∠FGH
= 180° - 52° - 52°
= 76°
Answer(s): (a) 115°; (b) 76°