PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 48°, ∠EFG = 124° and ∠HJF = 67°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 48°
= 42° (Angles sum of triangle)
∠HFJ
= 180° - 67° - 42°
= 71° (Angles sum of triangle)
∠EFJ
= 180° - 71°
= 124° (Angles on a straight line)
(b)
∠HFG
= 360° - 124° - 71° - 124°
= 41° (Angles at a point)
∠FGH
= 180° - 41° - 41°
= 98°
Answer(s): (a) 124°; (b) 98°