PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 51°, ∠KLM = 122° and ∠NPL = 68°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 51°
= 39° (Angles sum of triangle)
∠NLP
= 180° - 68° - 39°
= 73° (Angles sum of triangle)
∠KLP
= 180° - 73°
= 122° (Angles on a straight line)
(b)
∠NLM
= 360° - 122° - 73° - 122°
= 43° (Angles at a point)
∠LMN
= 180° - 43° - 43°
= 94°
Answer(s): (a) 122°; (b) 94°