PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 54°, ∠EFG = 113° and ∠HJF = 65°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 54°
= 36° (Angles sum of triangle)
∠HFJ
= 180° - 65° - 36°
= 79° (Angles sum of triangle)
∠EFJ
= 180° - 79°
= 113° (Angles on a straight line)
(b)
∠HFG
= 360° - 113° - 79° - 113°
= 55° (Angles at a point)
∠FGH
= 180° - 55° - 55°
= 70°
Answer(s): (a) 113°; (b) 70°