PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 53°, ∠EFG = 122° and ∠HJF = 64°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 53°
= 37° (Angles sum of triangle)
∠HFJ
= 180° - 64° - 37°
= 79° (Angles sum of triangle)
∠EFJ
= 180° - 79°
= 122° (Angles on a straight line)
(b)
∠HFG
= 360° - 122° - 79° - 122°
= 37° (Angles at a point)
∠FGH
= 180° - 37° - 37°
= 106°
Answer(s): (a) 122°; (b) 106°