PSLE In the figure, KLN and QPN are straight lines and PL is parallel to NM. ∠PQK is a right angle, ∠QKL = 50°, ∠KLM = 115° and ∠NPL = 69°.
- Find ∠KLP.
- Find ∠LMN.
(a)
∠KNQ
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠NLP
= 180° - 69° - 40°
= 71° (Angles sum of triangle)
∠KLP
= 180° - 71°
= 115° (Angles on a straight line)
(b)
∠NLM
= 360° - 115° - 71° - 115°
= 59° (Angles at a point)
∠LMN
= 180° - 59° - 59°
= 62°
Answer(s): (a) 115°; (b) 62°