PSLE In the figure, CDF and HGF are straight lines and GD is parallel to FE. ∠GHC is a right angle, ∠HCD = 49°, ∠CDE = 119° and ∠FGD = 62°.
- Find ∠CDG.
- Find ∠DEF.
(a)
∠CFH
= 180° - 90° - 49°
= 41° (Angles sum of triangle)
∠FDG
= 180° - 62° - 41°
= 77° (Angles sum of triangle)
∠CDG
= 180° - 77°
= 119° (Angles on a straight line)
(b)
∠FDE
= 360° - 119° - 77° - 119°
= 45° (Angles at a point)
∠DEF
= 180° - 45° - 45°
= 90°
Answer(s): (a) 119°; (b) 90°