PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 50°, ∠EFG = 122° and ∠HJF = 71°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠HFJ
= 180° - 71° - 40°
= 69° (Angles sum of triangle)
∠EFJ
= 180° - 69°
= 122° (Angles on a straight line)
(b)
∠HFG
= 360° - 122° - 69° - 122°
= 47° (Angles at a point)
∠FGH
= 180° - 47° - 47°
= 86°
Answer(s): (a) 122°; (b) 86°