PSLE In the figure, EFH and KJH are straight lines and JF is parallel to HG. ∠JKE is a right angle, ∠KEF = 55°, ∠EFG = 119° and ∠HJF = 70°.
- Find ∠EFJ.
- Find ∠FGH.
(a)
∠EHK
= 180° - 90° - 55°
= 35° (Angles sum of triangle)
∠HFJ
= 180° - 70° - 35°
= 75° (Angles sum of triangle)
∠EFJ
= 180° - 75°
= 119° (Angles on a straight line)
(b)
∠HFG
= 360° - 119° - 75° - 119°
= 47° (Angles at a point)
∠FGH
= 180° - 47° - 47°
= 86°
Answer(s): (a) 119°; (b) 86°