PSLE In the figure, JKM and PNM are straight lines and NK is parallel to ML. ∠NPJ is a right angle, ∠PJK = 50°, ∠JKL = 116° and ∠MNK = 70°.
- Find ∠JKN.
- Find ∠KLM.
(a)
∠JMP
= 180° - 90° - 50°
= 40° (Angles sum of triangle)
∠MKN
= 180° - 70° - 40°
= 70° (Angles sum of triangle)
∠JKN
= 180° - 70°
= 116° (Angles on a straight line)
(b)
∠MKL
= 360° - 116° - 70° - 116°
= 58° (Angles at a point)
∠KLM
= 180° - 58° - 58°
= 64°
Answer(s): (a) 116°; (b) 64°